Can someone tell me how can I calculate the angle (0-359)
between 2 entities? Here is what I've done so far :

Code:

---

dx = my.x - you.x;
dy = my.y - you.y;

angle = fatan(dy,dx);

---

The angle always return +/- 90 only.

Thanks.

vec_set(temp,you.x);
vec_sub(temp,my.x);
vec_to_angle(temp_angle,temp);

in this case temp_angle = angle to turn to look at second entity so it's different between entitys.
This is what you want?

and if you insist on using ur own trigonometry you need to write an atan2 function which'll return between +-180 (unless you have the latest A7 private-beta).

it just so happens i have one in my back-pocket (changed to work with c-script but untested):
Code:

---

function atan2(var x,var y)
{
	if(y==0)
	{
		return (90*sign(x));
	}
	return(atan(x/y) - (180 * (y<0)));
}

---

julz

Nope, thanks. The 'you' entity will move around the centre of 'my'
entity at runtime, I want to calculate the angle (0-359 degrees) of
the 'you' entity, which will return 0 degree when 'you' face at 'my'
and 180 degree when 'you' is behind 'my' entity.

Hope that clear.

this is what I use:

Code:

---

vec_set(temp,Node_pos);
vec_sub(temp,my.x);
vec_to_angle(myang,temp);
myang.pan = ang(myang.pan);

---

Hi Slin,

Your code looks very close, but still return negative
value when the 'you' entity move to the right side of
'my'. Can you help me a little bit more to solve this
problem? I want it to return 0 to 359 degree.

I'm sorry but I'm too tired right now after eating some
pills.....zzzzzzz.

so maybe use abs to avoid negative values?

Ok, I think I got it :

Code:

---

vec_diff(temp,you.x,my.x);
vec_to_angle(angle,temp);
angle %= 360;

---

Do you think so? if not please comment.
Thank you all.

What Tompo wrote should exactly be what you are looking for, isn´t it?
It is the same as that what I wrote just without the ang(); wich causes the -180/180 range.

Ah yes, I'm just thinking you guys will improve my
previous code using fatan(...) Well, sorry for that.