I've just recently gotten into structs and arrays, and was wondering if there was a better or more organized way initialize struct arrays:

typedef struct
{
char name[10];
int bas_hp;
int bas_att;
int bas_def;
int bas_acc;
int bas_eva;
} JOB;

JOB job[5];

void job_init ()
{
(job[0]).name = "Thief";
(job[0]).bas_hp = 9;
(job[0]).bas_att = 4;
(job[0]).bas_def = 3;
(job[0]).bas_acc = 6;
(job[0]).bas_eva = 3;
}

Thanks in advance.

if i've understood you correct that's the code yo initialise all jobs in array

Code:

---

typedef struct
{
char name[10];
int bas_hp;
int bas_att;
int bas_def;
int bas_acc;
int bas_eva;
} JOB;

JOB job[500];

void job_init (JOB* jb)
{
jb.name = "Thief";
jb.bas_hp = 9;
jb.bas_att = 4;
jb.bas_def = 3;
jb.bas_acc = 6;
jb.bas_eva = 3;
}

void init_all_jobs()
{
var num = 0;
while(num<499)
{
job_init (job[num]);
num+=1;
}
}

---

Thanks for the reply, however my intention was to give each job[x] a different initial value. I was wondering if there was an easier way to assign values in structs rather than typing out (job[x]).var1 = ...;

Sorry I didn't make myself clear.

maybe that'll help you

void job_init (JOB* jb, char* name, var hp, var att, var def, var acc, var eva)
{
jb.name = name;
jb.bas_hp = hp;
jb.bas_att = att;
jb.bas_def = def;
jb.bas_acc = acc;
jb.bas_eva = eva;
}

initialisation and setting all parameters in one function

Thank you very much, this was just what I was looking for!