this doesnt work (asd!=2). why?

coincidence. you just happen to ask about things i know

function test(var* num){
*num = 2;
}

var asd=0;
test(&asd);

Just to let you know, a pointer is an address. In this case, an address of a var. So it points to the var. When you say *num, it means whatever is pointed by num, in this case, asd and sets it to 2. And over here: test(&asd), you have to pass the address of asd to the function, or else it just creates a local copy and cannot edit it. Go read up on some ANSI C if you want to truly understand pointers. And, please don't use ent.x if you defined something like ENTITY* ent = ent_create(); Use ent->x. It's standard C, you know.

when you say test(asd); and use asd as a pointer, lite-c understands that and gives you it's pointers, so when you are using lite-c functions you GENARALLY wont need the preceeding &. Altough lite-c is fully compatible with ANSI-C, lite-c is not ANSI.

(so you can both pass a VECTOR or a VECTOR* to a function that takes VECTOR* as parameter)

oh well. Still, I like my old code format. It's more understandable.

compiler says "dimension of array error."
in
"*mat[i][j]=1;"
and
"*mat[i][j]=0;"

Whats wrong here?
Maybe because he is only passing a pointer to a single var in an array? (but (var** mat) doenst work too)

it should be make_identity_matrix(var mat[][4]); Arrays are basically pointers. And you do mat[i][j] instead of *mat[i][j].

BTW, the lite-c function 'mat_identity' makes a matrix into the identity matrix.