indicator of indicator, using series()

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indicator of indicator, using series() #445761 09/23/14 16:05 09/23/14 16:05
Joined: Apr 2014 Posts: 45 Germany webradio OP Newbie
webradio OP Newbie Joined: Apr 2014 Posts: 45 Germany	Intending two build a ten-period EMA of two-period ATR, is the following script an appropriate way? Code: var Ema_of_Atr(int Period) { var emaofatr = series(EMA(series(ATR(2)), 10)); return emaofatr; } I still have to get used to series()

Re: indicator of indicator, using series() [Re: webradio] #445764 09/23/14 17:36 09/23/14 17:36
Joined: Jul 2000 Posts: 28,131 Frankfurt jcl Chief Engineer
jcl Chief Engineer Joined: Jul 2000 Posts: 28,131 Frankfurt	Almost. But you're returning a series, so you need to declare var *Ema_of_Atr(int Period) or vars Ema_of_Atr(int Period)

Re: indicator of indicator, using series() [Re: jcl] #445768 09/23/14 20:29 09/23/14 20:29
Joined: Apr 2014 Posts: 45 Germany webradio OP Newbie
webradio OP Newbie Joined: Apr 2014 Posts: 45 Germany	Thanks for explaination, jcl! Shoudn't it be one asterisk less then? Otherwise it attempts to return a double Code: return emaofatr; After reading indicators.c, next question arose. Is there a valid reason at all, to return series when writing an indicator? Like intention of further processing? As far as I can see, all delivered indicators return double. So my script would shrink to Code: var Ema_of_Atr_simple() { return EMA(series(ATR(2)), 10); } And yet another one, about TSI Code: // Trend Strength Index, from Engineering Returns var TSI(var* Data,int Period) { var* ratio = series(abs(Data[0]-Data[Period])/ATR(Period),0); var* TSI = series(SMA(series(SMA(ratio,Period),0),10Period),0); return TSI; } As far as I can see it returns duble. Wouldn't it be simpler to Code: return SMA(series(SMA(ratio,Period),0),10*Period);

Re: indicator of indicator, using series() [Re: webradio] #445903 09/29/14 11:59 09/29/14 11:59
Joined: Jul 2000 Posts: 28,131 Frankfurt jcl Chief Engineer
jcl Chief Engineer Joined: Jul 2000 Posts: 28,131 Frankfurt	You're right, I had not seen that you're returning the last value of the series only, so your original definition was correct - and the series is not needed at all when you only return its last element.

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