Hi, i don't know if this has already been suggested as i have'nt read every single line but I do mechanics at school and this seems to be a common projectiles question.

The only thing missing is the distance from the ball to the player, but i guess that could be calculated with a vector function or something like that. Once you have the distance the ball is from the player, the time can be found easily.

u = inital velocity
Z = angle to ground
g = acceleration due to gravity (9.8)
t = time

Here are 4 equations of projectile motion...

Displacement (x) = utcosZ
Displacement (y) = utsinZ - 0.5gt^2

Velocity (x) = ucosZ
Velocity (y) = usinZ - gt

Example: distance to player is 30, angle is 15 and intial velocity is 10, trying to find time takes to reach player.

Horizontal velocity = 10cos15 = 9.66....

time = distance/speed = 30/9.66 = 3.11

I know I haven't explained it the best I could, but hopefully this could point you in the right direction.

Sorry if any of this has been mentioned before or that it is totally useless.

DJB MASTER...