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Dice roll question #303510
12/29/09 13:20
12/29/09 13:20
Joined: Mar 2007
Posts: 112
MikeS Offline OP
Member
MikeS  Offline OP
Member

Joined: Mar 2007
Posts: 112
Hi guys, i need your help.

I need to do some dice rolls for my project.

i need 2D6 roll and 1D6 roll.

I actually use this code for it:

Code:
result = max(1,(min(int(random(7)),6)));// 1D6 roll

Hit_roll = max(2,(min(int(random(13)),12))); //2D6 roll


but my problem with this code is the following:

with this codes i have a much too high chance for the 1 (1D6 roll)
and for the 2 (2D6 roll)

maybe someone has a good sollution for this?

i want to have the same chances for each number

Greetings

Mike

Re: Dice roll question [Re: MikeS] #303511
12/29/09 13:25
12/29/09 13:25

M
mercuryus
Unregistered
mercuryus
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result = integer(random(6))+1; // 1..6
Hit_roll = integer(random(11))+2; // 2..12


Re: Dice roll question [Re: ] #303518
12/29/09 15:44
12/29/09 15:44
Joined: Mar 2007
Posts: 112
MikeS Offline OP
Member
MikeS  Offline OP
Member

Joined: Mar 2007
Posts: 112
great, thank you, it worked.

Greetings Mike

Re: Dice roll question [Re: MikeS] #303527
12/29/09 18:08
12/29/09 18:08
Joined: May 2007
Posts: 2,043
Germany
Lukas Offline

Programmer
Lukas  Offline

Programmer

Joined: May 2007
Posts: 2,043
Germany
But actually, if you roll two dices, different numbers have a different propability.

Hit_roll = integer(random(6))+integer(random(6)+2;

This is like real dices.

Re: Dice roll question [Re: Lukas] #303539
12/29/09 19:48
12/29/09 19:48

M
mercuryus
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mercuryus
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lol


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