I know, it works but not the way I want it to... Need to calculate in x coordinates, and make player leave the ladder as soon, as he turns away from it... But have no idea how to make all that...

Can some very kind person, help me to calculate dist from ladder to player in X coordinates? It's already done, but only in Y and Z coordinates... Need the same thing but only in X coordinates. I know, I'm not making any sense by just always asking for it... But this piece of player movemet really makes me going crazy... I've done every thing in player movement script for my FPS game called War Cloud. Only two things left... First is this ladder script (damn I really hate it )... And second is elevators, but it will be easy to do... With help of AUM tutorials I've tryed to get all that to work by myself... You can see it from my scripts I've posted... But I always fail can't make the player leave the damn ladder when he walks away from it in X coordinates...

Really need some ones help I can't figure out this alone...

Try something like,
if (player.pan && (player.z = ?)
{
exit ladder;
return;
}

I've tried similar to Z coordinates, like this:
if(player.x + player.min_x - 30 > my.max_x)
{
break;
climb = 0;
}
But not working any way... played with 30, doesn't make any sense... Now I hate ladder man...

No one giving me the answer, for question I'm asking for... Is that so hard to help such newbie as me? Only thing I'm asking for is calculating distanse from ladder to player as it is already done in Y coordinates, need the same, but only in X coordinates, so if player for example walks backwards (or forward) from the ladder, and distanse is bigger for example than 15 (or smaller than -15), then player must leave the ladder... Will be very effective to create a ladder script I guess... I've stucked in this damn piece of script... no problem with leaving the ladder, if player turned away from it, I'll fix it on myself, that will be very easy, player will be not able to turn away from it, he can only look around. I understand that I'm really badass and may be even asking too much, but I really stuck here please some one, be so kind and help me. I'll be really grateful and will add name of person who will help me out, in the credits of my game, as a programmer that helped me with my game...

if(vec_dist(vector(ladder.x,ladder.y,0),vector(player.x,player.y,0)) > 20) {}

Thank you bro, but I've tried like that already... Doesn't work it calculates distanse only from the center of the model... Works if player is in the middle of the ladder... If in the top for example, doesn't help...

Is your ladder actually upright? Superku's line should work independently whether the player is in the middle or at any end of the ladder, because of the zero at the z value of the vectors.

Just an idea, replace "0" in both vectors by "player.z".

Now it works well... Just need some testing and ladder script need some improvements Thank you Superku!!! You're the best! I'll add you in the credits of my project Thank you all!