Do the vector(90,90,200) make the 90x90 size?

Have you read the c_scan description in the manual? There is everything you need to know.

Yes i did. Perhaps that description isn't clear for me. I wasn't born in english speaking country. But if the manual is so short in describing that function i have to on to another solution for my problem.

c_scan (VECTOR* pos, ANGLE* ang, VECTOR* sector, var mode);

When you look "from above" into your level, f.i. use the xy-Top-Down-View in WED as an illustration, sector.x is the width of your c_scan in degrees (0..360).
Example:
sector.x = 90;
camera.pan = 0. => scan-cone.pan = -45..45, //the value is centered around your camera.pan

When you look from the side in WED (xz,yz), sector.y ( = alpha = 45° in the image) determines the scan height in degrees.


sector.y behaves the same way as sector.x does, if your camera.tilt = 20 and sector.y is 25, your scan-tilt-angle will be -5..45. (camera.tilt-sector.y to camera.tilt+sector.y).

Be aware of the shape of a cone, c_scan is not a cylindrical scan.

Thank you Superku, it is much more clearer now for me. I appreciate your work to teach me.

What do you think, how should implement an always visible, half transparent square in front of the camera at 150 distance?
It would be useful to check the proper c_scan usage for me.