I'm thinking that the following should work:

function run()
{
vars P=series();
vars high=series(priceHigh());
int highndx;
int i;

for(i=0;i=LOOKBACK;i++)
{
if(high[i]<high[i+1])
{
highndx = i+1;
break;
}
}

P[0]=high[highndx];

}

But I am obviously wrong as I get a syntax error on the P[0]=high[highndx] . Pretty certain the problem has something to do with pointers. This hsa to be something stupid that I have missed because it it too stupid. Certainly you can move an array value to an array value.
Thanks
P
edit where error is.

Your code has no syntax error. But it has an infinite loop. Can someone find it?

I been looking at this tooo long.
There is only one loop, so it has to be infinite, but I don't see it.
Break should exit the for when the condition matches.
so either the condition will never match or i will never be equal to loopback.
P

LookBack is not defined, so zorro tries to calculate it by adding one each time?

for (initialization; comparison; continuation) { ... }

i=LOOKBACK is NOT comparison.

That's what's obvious, without running the script..

Try i<LookBack for your comparison (and also not i==LookBack)

edit: i guess your i=LookBack assignment always returns true thus your loop runs endlessly(am i right?)

Yes, the comparison is wrong and LOOKBACK is a flag - what you meant was LookBack. C is case sensitve.

The "P[0]=high[highndx];" line however is correct.

Thanks All,
Appreciate the help.
The LOOKBACK being a flag was not a problem I was thinking about.
Good to know there is an option.
Changing code feverisly
I seem to struggle with some of the more simple concepts of C.
P