I did find this:

Quote:

rot. a = torque / I, or
torque = I*(rot. a)



(the distribution of mass affects I, so let's just say the mass is equally distributed)

So in my example,

rot.a = 500/10

so,

rot.a = 50 degrees per tick added to the rotational velocity.

Is that right?

Last edited by A.Russell; 03/20/06 05:41.
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