How to write dataParseJSON format correctly ?

Hello,

I want to convert json to t6 by using dataParseJSON.

+%t,f3,f1,f2,f4,f6 works for csv but with json I don't know how to write correctly. Anyone here can help me ?

This is api json I want to get


This is json format in manual page:

I changed to "+%t,open,high,low,close" but it still show error.

No, it's not possible! As you can see, the json you receive contains unnamed fields, so you can't reference them by name in your format string.