Displaying pointers with diag statement

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Displaying pointers with diag statement #469522 11/19/17 15:25 11/19/17 15:25
Joined: Sep 2009 Posts: 993 Budapest Aku_Aku OP User
Aku_Aku OP User Joined: Sep 2009 Posts: 993 Budapest	Hello Community! I would like to know your opinion this code, i want to display a pointer with diag. Code: typedef struct MY_DEF { int my_number; } MY_DEF; MY_DEF* my_type; my_type = malloc(sizeof(MY_DEF)); diag(str_printf(str, "nPointer:%d",(long)my_type)); Do you see any problem with this code?

Re: Displaying pointers with diag statement [Re: Aku_Aku] #469524 11/19/17 17:09 11/19/17 17:09
Joined: Oct 2007 Posts: 5,210 İstanbul, Turkey Quad Senior Expert
Quad Senior Expert Joined: Oct 2007 Posts: 5,210 İstanbul, Turkey	normally in C you would do: Code: str_printf(str, "nPointer:%p",(void)my_type) (notice %p and void cast) but i am not sure how lite-c actually handles pointers internally so results may vary. Edit: you get different results either way depending on whether PRAGMA_POINTER is defined or not. Last edited by Quad; 11/19/17 17:13. 3333333333

Re: Displaying pointers with diag statement [Re: Quad] #469528 11/19/17 22:46 11/19/17 22:46
Joined: Sep 2009 Posts: 993 Budapest Aku_Aku OP User
Aku_Aku OP User Joined: Sep 2009 Posts: 993 Budapest	Thanks, it seems to me it is better than mine, furthermore p is a regular type in formatting strings. I tried this format, and finally i will stay with my original type, because (str, "nPointer:%p",(void*)my_type) gives back a hexadecimal number, mine gives back a decimal number. Last edited by Aku_Aku; 11/19/17 22:53. Reason: final solutions