Quote:

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I think you can prove that 2048 can not have an even divisor between 64 and 128:

2048 is 2*2*2...*2. Suppose it had an even divisor u that is not a power of 2, then 2048 = u*v = (2*2*2..*n)*(2*2*2..*m) = (2*2*2..)*(m*n), while n and m both are >1 and odd. This however is not possible because (m*n) then is also odd and can't result in 2048 when multiplied with a power of 2.

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Get off your mathematician ass and go rollerblading... you make our heads hurt

Nice one, Doug. Gotta admit though, I recognize what you're doing, but don't have the slightest idea how it's actually figured mathematically anymore.

-Rhuarc

IsEvenDivisor(Divisor, Value)
{
   return Value / Divisor == int(Value / Divisor)
}

..
i = 65;
while(i < 128)
{
   if(IsEvenDivisor(i, 2048))
   {
      EvenDivisors += 1;
   }
   i += 1;
}