Looks who's back, back again....

I'm trying to get the length of an array. According to SO posts and C manuals this is achievable using sizeof()

I have got the size of a single array element but the size of the whole array is not retrieved properly. I'm certain I've done this correctly according to C rules but maybe it's different in lite-C? Is there a way to get an array length in lite-C?
Code:
void main()
{	
	int tfArray[3] = {5,60,1};

	//get the size of the whole array
	int arSize = sizeof(tfArray);
	//get the size of the first element in the array
	int arElementSize = sizeof(&tfArray[0]);
	//get the array length
	int arLen = sizeof(tfArray)/sizeof(&tfArray[0]);
	
	//report what we find
	printf("nArray size in bytes = %i", arSize);
	printf("nArray element size in bytes = %i", arElementSize);
	printf("nArray length = %i", arLen);
}

Cheers,
BobbyT

EDIT: I have also tried the malloc/free trick (I think) but the values returned are way off. I feel I'm closer but, not by much. Here's the code implementing the use of malloc/free/memory:
Code:
function main()
{	
	int tfArray[3] = {5,60,1};
	
	printf("nMemory before malloc is %i", memory(0));
	
	int array = malloc(tfArray);
	int mem = memory(0);
	
	printf("nMemory after malloc is %i", memory(0));
	
	free(array);
	
	printf("nMemory after free is %i", memory(0));
	
	//get the size of the whole array
	int arSize = mem - memory(0);	
	//get the size of the first element in the array
	int arElementSize = sizeof(&tfArray[0]);
	//get the array length
	int arLen = arSize/sizeof(&tfArray[0]);
	
	//report what we find
	printf("nArray size in bytes = %i", arSize);
	printf("nArray element size in bytes = %i", arElementSize);
	printf("nArray length = %i", arLen);
}

Last edited by BobbyT; 07/18/17 03:28.