Thank you, brax! It makes sense.

What do you mean by static exit?

Please see 2 examples:
1st example: First optimize entry parameters + static stop=4*atr(100). Then optimize entry parameters with stop=optimize(4,2,10)*atr(100). No problem here, optimized entry parameters will be the same in both optimization cycles.

2nd example: first optimize entry parameters + reversal exit (I don't know whether we can name this exit static but it's definitely simple). Then optimize entry parameters with stop limit. There was no stop limit on the first step. So when we optimize the second time with stop, the entry parameters will be different.

Do you understand my concerns?